(3x^2+4)/(2x+1)=0

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Solution for (3x^2+4)/(2x+1)=0 equation: 



(3x^2+4)/(2x+1)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R



We multiply all the terms by the denominator


(3x^2+4)=0

We get rid of parentheses

3x^2+4=0

a = 3; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·3·4
Δ = -48
Delta is less than zero, so there is no solution for the equation

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